J'ai ce tableau ;

| x | -2 | 0 | 5 |
|-----+----+---+---|
| 2 x | | | |
|-----+----+---+---|
| x^2 | | | |
|-----+----+---+---|

Je souhaiterai que les formules de la colonne de gauche soient évaluéeq pour
les valeurs de x de la première rangée.

J'ai essayé subst($1,@1$1,@1) et ça ne fait pas ce que
j'attends. la substitution est bien faite, mais le résultat n'est pas
évalué.

| x | -2 | 0 | 5 |
|-----+--------+-----+-----|
| 2 x | 2*-2 | 2 0 | 2 5 |
|-----+--------+-----+-----|
| x^2 | (-2)^2 | 0^2 | 5^2 |
|-----+--------+-----+-----|
#+TBLFM: @<<$<<..@>$>=subst($1,@1$1,@1)::@2$1=deriv(@3$1,@< $<);E

En mode calc, subst(2 x,x,5) renvoie bien 10.

J'ai essayé quelque chose comme apply ou eval, mais ça ne va pas.
Il y a quelque chose qui a du m'échapper dans le info de org ou de
calc.

dim. 14 janv. 2018, jj.retorre (Jean-Jacques Rétorré) disait :

[..]
> | x^2 | (-2)^2 | 0^2 | 5^2 |
> |-----+--------+-----+-----|
> #+TBLFM: @<<$<<..@>$>=subst(,@1,@1)::@2=deriv(@3,@<$<);E
> En mode calc, subst(2 x,x,5) renvoie bien 10.
> J'ai essayé quelque chose comme apply ou eval, mais ça ne va pas.
> Il y a quelque chose qui a du m'échapper dans le info de org ou de
> calc.

J'ai eu une réponse sur emacs.stackexchange, il suffit d'appliquer
simplify à subst

| x | -2 | 0 | 5 | a+1 |
|-----+----+---+----+-----------|
| 2 x | -4 | 0 | 10 | 2 a + 2 |
|-----+----+---+----+-----------|
| x^2 | 4 | 0 | 25 | (a + 1)^2 |
|-----+----+---+----+-----------|
#+TBLFM: @<<$<<..@>$>=simplify(subst($1,@1$1,@1))::@2$1=der iv(@3$1,@<$<);E

Voilà..

mer. 17 janv. 2018, jj.retorre (Jean-Jacques Rétorré) disait :

> dim. 14 janv. 2018, jj.retorre (Jean-Jacques Rétorré) disait :
> simplify à subst
> | x | -2 | 0 | 5 | a+1 |
> |-----+----+---+----+-----------|
> | 2 x | -4 | 0 | 10 | 2 a + 2 |
> |-----+----+---+----+-----------|
> | x^2 | 4 | 0 | 25 | (a + 1)^2 |
> |-----+----+---+----+-----------|
> #+TBLFM: @<<$<<..@>$>=simplify(subst(,@1,@1))::@2=deriv(@3, @<$<);E
> Voilà..

On peut aussi bien appliquer expand ou factor et peut-être d'autres
fonctions selon le résultat désiré.

Le dimanche 14 Janvier 2018 à 19:36 par jj.retorre :
[..]
> @<<$<<..@>$>=3Dsubst(,@1,@1)::@2=3Dderiv(@3,@<$<); E
> En mode calc, subst(2 x,x,5) renvoie bien 10.
> J'ai essay=C3=A9 quelque chose comme apply ou eval, mais =C3=A7a ne va pas.
> Il y a quelque chose qui a du m'=C3=A9chapper dans le info de org ou de
> calc.
> --
> JJR
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jj.retorre (Jean-Jacques Rétorré) writes:

> mer. 17 janv. 2018, jj.retorre (Jean-Jacques Rétorré) disait :
>> On peut aussi bien appliquer expand ou factor et peut-être d'autres
> fonctions selon le résultat désiré.

En fait c'était plus une question Calc qu'une question
org-mode. Peut-être aurais-tu dû essayer directement d'évaluer ceci :

(calcFunc-subst (calc-eval "2*x" 'raw) (calc-eval "x" 'raw) 2 )

Tu aurais eu cela :

(* 2 2)

Ou encore en evaluant :

(math-format-flat-expr
(calcFunc-subst (calc-eval "2*x" 'raw) (calc-eval "x" 'raw) 2)
calc-internal-prec)

Tu aurais eu cela :

"2 * 2"

Vincent.

ven. 26 janv. 2018, vincent.belaiche (Vincent Belaïche) disait
:

[..]
> Ou encore en evaluant :
> (math-format-flat-expr
> (calcFunc-subst (calc-eval "2*x" 'raw) (calc-eval "x" 'raw) 2)
> calc-internal-prec)
> Tu aurais eu cela :
> "2 * 2"

Certes. La documentation des fonctions calc, c'est bien souvent « not
documented ». ça ne donne pas envie de les utiliser.

,----
| (describe-function 'math-format-flat-expr)
| #("math-format-flat-expr is a compiled Lisp function in ?calc.el?.
|
| (math-format-flat-expr A PREC)
|
| Not documented.
|
| (describe-function 'calcFunc-subst)
| #("calcFunc-subst is an alias for ?math-expr-subst? in ?calc-alg.el?.
|
| (calcFunc-subst EXPR MATH-EXPR-SUBST-OLD MATH-EXPR-SUBST-NEW)
|
| Not documented.
`----

jj.retorre (Jean-Jacques Rétorré) writes:

> ven. 26 janv. 2018, vincent.belaiche (Vincent Belaïche) disait
> :
>> Certes. La documentation des fonctions calc, c'est bien souvent « not
> documented ». ça ne donne pas envie de les utiliser.

Oui, il ne faut pas faire `C-h f', mais `h f' dans le tampon *Calc*, et
là tu tapes le nom de la fonction calc subst (et non le nom Lisp
calcFunc-subst). Alors ça te mène dans le manuel à l'endroitoù la
fonction est documentée.

>> ,----
> | (describe-function 'math-format-flat-expr)
> | #("math-format-flat-expr is a compiled Lisp function in ?calc.el?.
> |
> | (math-format-flat-expr A PREC)
> |
> | Not documented.

Ok pour math-format-flat-expr ce n'est pas une fonction calc, donc le `h
f' ne marche pas, ceci dit tu la trouveras dans le manuel là:

(info "(calc) Formatting Lisp Functions")

Je m'aperçois d'ailleurs qu'il fallait passer 0 à PREC, et non
calc-internal-prec.

> |
> | (describe-function 'calcFunc-subst)
> | #("calcFunc-subst is an alias for ?math-expr-subst? in ?calc-alg.el?.
> |
> | (calcFunc-subst EXPR MATH-EXPR-SUBST-OLD MATH-EXPR-SUBST-NEW)
> |
> | Not documented.
> `----

Là ça marche de faire `h f'.

V.

> --
> JJR.